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5x^2+28x-76=0
a = 5; b = 28; c = -76;
Δ = b2-4ac
Δ = 282-4·5·(-76)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-48}{2*5}=\frac{-76}{10} =-7+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+48}{2*5}=\frac{20}{10} =2 $
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